#純靠北工程師3z2
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今天教各位如何用C++寫忍者code（閏年判斷為例）
正常人︰
```
int year = 2020;//year:今年
if(
(
year % 4 == 0
&& year % 100 != 0
) ||
year % 400 == 0
)//分支
cout << "Yes"; //成立
else cout << "No";//不成立
```
忍者︰
```
const char* _[2] = {"No","Yes"};
int __nj_ = 2020;
std::cout << _[!(__nj_&3)&&__nj_%25||!(__nj_&15)];
```
各位想當忍者嗎？
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